CSIR UGC NET Result 2024: The National Testing Agency (NTA) is preparing to release the results and final answer keys for the Council of Scientific and Industrial Research National Eligibility Test (Joint CSIR UGC-NET) soon. According to the media reports, students can expect their scorecards this week. However, no official date is released yet. Once the scorecards are out, students can download it from the official website of CSIR at csirnet.nta.ac.in.

Along with the announcement of the results, the CSIR UGC NET cut-off 2024 and final answer key will be made available as a PDF on the official website. To view their results and scorecard, applicants must first log into their registered account.

The CSIR UGC NET July 2024 exam was held on July 25, 26, and 27, 2024, using a CBT format. Approximately 2 lakh students took the exam. The provisional answer keys were made available on August 9. Applicants could raise objections by paying a cost of Rs. 200 per question. Based on this, the testing agency will issue the final answer keys and results.

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To pass the CSIR UGC NET exam in July 2024, applicants from the General, EWS, and OBC categories must score at least 33 per cent marks, while the SC, ST, and PwD category applicants should secure atleast 25 per cent.

The Joint CSIR UGC NET is a test used to evaluate if Indian citizens are eligible for Junior Research Fellowship (JRF), Assistant Professor, and admission to Ph.D. programs at Indian universities and colleges, provided they match the UGC's eligibility criteria.

How to download the CSIR UGC NET 2024 Result?

To download and check the UGC NET 2024 Result, candidates have to follow the mentioned below steps:-

Step 1: Visit the official website of CSIR NET at csirnet.nta.ac.in.

Step 2: Click on the "Joint CSIR UGC-NET Result 2024," available on the homepage.

Step 3: After this, enter the necessary details such as the application number, DOB etc.

Step 4: Now, the CSIR UGC-NET Result 2024 will displayed on the screen.

Step 5: Download the CSIR UGC-NET Result 2024 and take a printout of the same for further reference.

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